In an election, the i-th vote was cast for persons[i] at time times[i]. Now, we would like to implement the following query function: TopVotedCandidate.q(int t) will return the number of the person that was leading the election at time t. Votes cast at time t will count towards our query. In the case of a tie, the most recent vote (among tied candidates) wins. Example 1: Input: ["TopVotedCandidate","q","q","q","q","q","q"], [[[0,1,1,0,0,1,0],[0,5,10,15,20,25,30]],[3],[12],[25],[15],[24],[8]] Output: [null,0,1,1,0,0,1] Explanation: At time 3, the votes are [0], and 0 is leading. At time 12, the votes are [0,1,1], and 1 is leading. At time 25, the votes are [0,1,1,0,0,1], and 1 is leading (as ties go to the most recent vote.) This continues for 3 more queries at time 15, 24, and 8. Note: 1 <= persons.length = times.length <= 5000 0 <= persons[i] <= persons.length times is a strictly increasing array with all elements in [0, 10^9]. TopVotedCandidate.q is called at most 10000 times per test case. TopVotedCandidate.q(int t) is always called with t >= times[0].