You are given a sorted integer array arr containing 1 and prime numbers, where all the integers of arr are unique. You are also given an integer k. For every i and j where 0 <= i < j < arr.length, we consider the fraction arr[i] / arr[j]. Return the kth smallest fraction considered. Return your answer as an array of integers of size 2, where answer[0] == arr[i] and answer[1] == arr[j]. Example 1: Input: arr = [1,2,3,5], k = 3 Output: [2,5] Explanation: The fractions to be considered in sorted order are: 1/5, 1/3, 2/5, 1/2, 3/5, and 2/3. The third fraction is 2/5. Example 2: Input: arr = [1,7], k = 1 Output: [1,7] Constraints: 2 <= arr.length <= 1000 1 <= arr[i] <= 3 * 104 arr[0] == 1 arr[i] is a prime number for i > 0. All the numbers of arr are unique and sorted in strictly increasing order. 1 <= k <= arr.length * (arr.length - 1) / 2