303.

Range Sum Query - Immutable

Easy

Given an integer array nums, find the sum of the elements between indices left and right inclusive, where (left <= right). Implement the NumArray class: NumArray(int[] nums) initializes the object with the integer array nums. int sumRange(int left, int right) returns the sum of the elements of the nums array in the range [left, right] inclusive (i.e., sum(nums[left], nums[left + 1], ... , nums[right])). Example 1: Input ["NumArray", "sumRange", "sumRange", "sumRange"] [[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]] Output [null, 1, -1, -3] Explanation NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]); numArray.sumRange(0, 2); // return 1 ((-2) + 0 + 3) numArray.sumRange(2, 5); // return -1 (3 + (-5) + 2 + (-1)) numArray.sumRange(0, 5); // return -3 ((-2) + 0 + 3 + (-5) + 2 + (-1)) Constraints: 1 <= nums.length <= 104 -105 <= nums[i] <= 105 0 <= left <= right < nums.length At most 104 calls will be made to sumRange.