Design an iterator to flatten a 2D vector. It should support the next and hasNext operations. Implement the Vector2D class: Vector2D(int[][] vec) initializes the object with the 2D vector vec. next() returns the next element from the 2D vector and moves the pointer one step forward. You may assume that all the calls to next are valid. hasNext() returns true if there are still some elements in the vector, and false otherwise. Example 1: Input ["Vector2D", "next", "next", "next", "hasNext", "hasNext", "next", "hasNext"] [[[[1, 2], [3], [4]]], [], [], [], [], [], [], []] Output [null, 1, 2, 3, true, true, 4, false] Explanation Vector2D vector2D = new Vector2D([[1, 2], [3], [4]]); vector2D.next(); // return 1 vector2D.next(); // return 2 vector2D.next(); // return 3 vector2D.hasNext(); // return True vector2D.hasNext(); // return True vector2D.next(); // return 4 vector2D.hasNext(); // return False Constraints: 0 <= vec.length <= 200 0 <= vec[i].length <= 500 -500 <= vec[i][j] <= 500 At most 105 calls will be made to next and hasNext. Follow up: As an added challenge, try to code it using only iterators in C++ or iterators in Java.