1545.

Find Kth Bit in Nth Binary String

Medium

Given two positive integers n and k, the binary string Sn is formed as follows: S1 = "0" Si = Si-1 + "1" + reverse(invert(Si-1)) for i > 1 Where + denotes the concatenation operation, reverse(x) returns the reversed string x, and invert(x) inverts all the bits in x (0 changes to 1 and 1 changes to 0). For example, the first 4 strings in the above sequence are: S1 = "0" S2 = "011" S3 = "0111001" S4 = "011100110110001" Return the kth bit in Sn. It is guaranteed that k is valid for the given n. Example 1: Input: n = 3, k = 1 Output: "0" Explanation: S3 is "0111001". The first bit is "0". Example 2: Input: n = 4, k = 11 Output: "1" Explanation: S4 is "011100110110001". The 11th bit is "1". Example 3: Input: n = 1, k = 1 Output: "0" Example 4: Input: n = 2, k = 3 Output: "1" Constraints: 1 <= n <= 20 1 <= k <= 2n - 1